Question

Two masses m1 and m2 are connected by means of a light string, that passes over a light pulley as shown in the figure. If m1=2 kg and m2=5 kg and a vertical force F is applied on the pulley, then find the acceleration of the masses and that of the pulley when. pls answer in the form an attachment (i.e solve it on a paper plss or else i would not accept ...so pls)..to any ans that i will understand properly will get a brainlist and 50 points

Answer 1

Given that,

Mass $m_{1}=2\ kg$

Mass $m_{2}=5\ kg$

Suppose, The force is 100 N.

According to figure,

String is same for both masses so the force will equally divided in the string.

We need to calculate the acceleration in first mass

Using balance equation

$F-mg=ma$

Put the value into the formula

$50-2\times9.8=2a$

$a=\dfrac{50-2\times9.8}{2}$

$a=15.2\ m/s^2$

We need to calculate the acceleration in second mass

Using balance equation

$F-mg=ma'$

Put the value into the formula

$50-5\times9.8=5a'$

$a'=\dfrac{50-5\times9.8}{5}$

$a'=0.2\ m/s^2$

Hence, The acceleration of the first  and second masses are 15.2 m/s² and 0.2 m/s².

Answer 2

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Sorry Dear, Don't Know But Above Answer is Right And It is Verified By Me.