Question

two masses m1 and m2 are connected with a string passing over the frictionless pulley fixed at the corner of the table is shown in the figure given below the question. The coefficient of static friction of mass M1 with the table is μs. calculate the minimum mass entry that may be placed on M1 to prevent it from sliding check if m1 = 15 kg M2 = 10 kg M3 = 25 kg and μ = 0.2.

Answer 1

60Kg as force m2 if 100N

=> and (m1 + m2)g =400N * meu (ie looks like U)

=> 40N

we need 100-40=60N

60N/0.1=600N

600N=Mg(gravity)

=>M=60Kg ans