Physics, asked by erajpoot777, 6 months ago

Two masses m1, and m2 are initially at rest with a spring compressed between
them. What is the ratio of the magnitude of their velocities after the spring has
been released?

Answers

Answered by urvashikumari12345
4

Explanation:

ANSWER

Initial momentum of the system is zero  i.e.  Pi=0

Let the velocity acquire by masses m1 and m2 just after they are released be v1 and v2.

Final momentum of the system  Pf=m1v1−m2v2

Using conservation of momentum :  Pi=Pf

∴  0=m1v1−m2v2

⟹  m1v1=m2v2          (v=dtdx)

⟹m1x1=m2x2

⟹  x2x1=m1m2

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Answered by nainaasghar84
0

Answer:

A will be answe it is correct

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