Question

Two masses m1 and m2 connected by means of a string which is made to pass over light , smooth pulley are in equilibrium on a fixed smooth wedge as shown in fiqure if teta is 60 degrees and alpha is 30 degrees, the ratio of m1 to m2 is plz its urgent.........reply me the answer soon...

Answer 1

Answer:

1:✓3

Explanation:

m1sin Teta=m2sin alpha

m1 sin60= m2 sin30

m1 ✓3/2 = m2 1/2

m1 ✓3 = m2

m1:m2 = 1:✓3

Answer 2

ANSWER:

The ratio of masses will be 1:√3.

EXPLANATION:

   As the masses are attached to the pulley in the downward directions, so the force will be having only its horizontal component acting on them. As the wedge to which the masses are attached are in equilibrium so the horizontal component of mass m1 will be equal to the horizontal component of mass m2.

$m 1 \sin 60^{\circ}=m 2 \sin 30^{\circ}$

Thus the ratio of the masses m1 and m2 will be

$\frac{m 1}{m 2}=\frac{\sin 30^{\circ}}{\sin 60^{\circ}}$

$\frac{m 1}{m 2}=\frac{1}{2} * \frac{2}{\sqrt{3}}=\frac{1}{\sqrt{3}}$

Thus the ratio of masses will be $1 : \sqrt{3}$.