Question

two masses of 1 gram in 9 grammar moving with equal Kinetic energies the ratio of the magnitude of their respective linear momentum is​

Answer 1

Answer:

p1:p2=1:3

Explanation:

applying p=√2Km

then p1=√2K1

p2=√2K9

therefore p1/p2=√2K/√2K9

on solving p1:p2=1:3

Answer 2

The ratio of the magnitude of their respective linear momentum is​ 1:3.

Explanation:

It is given that,

Mass of object 1, $m_1=1\ g$

Mass of object 2, $m_2=9\ g$

It is mentioned that tow masses move with equal kinetic energy. The relationship between the kinetic energy and the momentum is given by :

$E=\dfrac{p^2}{2m}$

Since, $E_1=E_2$

$\dfrac{p_1^2}{2m_1}=\dfrac{p_2^2}{2m_2}$

$\dfrac{p_1}{p_2}=\sqrt{\dfrac{m_1}{m_2}}$

$\dfrac{p_1}{p_2}=\sqrt{\dfrac{1}{9}}$

$\dfrac{p_1}{p_2}=\dfrac{1}{3}$

So, the ratio of the magnitude of their respective linear momentum is​ 1:3. Hence, this is the required solution.

Learn more,

Kinetic energy

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