two masses of 10 kg are placed at a distance of 1nm find the gravitational force with proper steps thnx
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Let the resultant gravitational intensity be zero at distance x from the mass of 10 kg on the line joining the centers of the two bodies. At this point, the gravitational intensities due to the two bodies must be equal and opposite.
∴x2Gx10=(1−x2)2Gx1000
or 100x2=(1−x)2 or 10x = 1 - x
or 11x = 1 or x = 1/11 m.
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