Question

Two masses of 3.5 kg and 10 kg are placed at a distance of

5 meter. Calculate the force of gravitation acting between them.​

Answer 1

Explanation:

f = force of gravitation

G = gravitational constant = 6.67 × 10^(-11)

m1 = Mass of object 1

m2 = Mass of object 2

r = distance between the objects

$f = \frac{g \times m1 \times m2}{ {r}^{2} }$

$= \frac{6.67 \times {10}^{ - 11} \times 3.5 \times 10 }{ {5}^{2} }$

$= \frac{6.67 \times {10}^{ - 11} \times 35 }{25} = 9.338 \times {10}^{ - 11}$

Therefore , it is your answer.

I hope it helps you. If you have any doubts, then don't hesitate to ask.

Answer 2

Given:-

→ Mass of the 1st body = 3.5kg

→ Mass of the 2nd body = 10kg

→ Distance between the masses = 5m

To find:-

→ Force of gravitation acting between the

masses.

Solution:-

By Newton's Universal Law of Gravitation , we know that :-

F = GMm/r²

Where :-

• F is the gravitational force of attraction

between the bodies.

• G is Universal Gravitational Constant.

• M is mass of the 1st body.

• m is mass of the 2nd body.

• r is the distance of separation between

the bodies.

→ Value of G = 6.67×10⁻¹¹ Nm²/kg²

By substituting the values, we get :-

=> F = 6.67×10⁻¹¹×3.5×10/(5)²

=> F = 6.67×10⁻¹¹×35/25

=> F = 6.67×1.4×10⁻¹¹

=> F = 9.338×10⁻¹¹ N

Thus, the force of gravitation acting between them is 9.338×10⁻¹¹ N .