Question

two masses of 3 kg and 2kg are attached to the end of string pass over a pulley fixed at the top what is tension and acceleration

Answer 1

m1 = 2kg
m2= 3kg
Now,
T= (2m1 × m2 / m1 × m2 )g
= (2 ×2 ×3/ 2+3 )g
= 12/5 g

a = (m2 - m1 / m1+ m2) g
= (3-2/3+2)g
= g/5

Answer 2

m1=2kg

m2=3kg

T=(2m1×m2/m1+m2)g

T=(2×2×3/2+3)g

T=12/5g

a=(m2-m1/m1+m2)g

a=(3-2/3+2)g

a=g/5