Question

Two masses of 3kg and 5kg are placed at 20cn and 70 cm marks respectively on a light wooden meter scale. What will be the moment of inertia

Answer 1

Since the scale is a rod its axis of rotation will be at centre

so Moment of inertia= mass*distance^2

=m1*r1^2+=m2*r2^2+

=3*(20*10^-2)^2+5*(20*10^-2)^2

=0.32kgm^2