Question

Two masses of 4kg and 6kg are hing from two identical springs. The two springs extend by a constant length for every kilogram of mass hung from them. If the final length of the two springs is 15cm and 18 cm respectively,what is the orginal length of the springs.​

Answer 1

Answer:

The spring constant can be found out by

k=

x

F

=

0.01

4×10

=4000N/m

Now, when two springs are connected in series, their equivalent constant is

k

eq

1

=

4000

1

+

4000

1

k

eq

=2000N/m

Therefore, mass of 6 kg will descend by

x=

2000

6×10

=0.03m=3cm

Step-by-step explanation:

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