Question

two masses of 500grams and 600 Grams attached to the 10 cm and 80 cm marks respectively of light metre scale the moment of inertia of the system about an Axis passing through the centre of the scales will be
A) 0.134kgm^2
B)0.56kgm^2
C)2kgm^2
D)4.5kgm^2​

Answer 1

Answer:

2kgm^2 is the answer of your questions

Answer 2

The moment of inertia of the system about an axis passing through the center of the scales will be $0.134\ kg-m^2$

Explanation:

Given that,

Mass 1, $m_1=500\ g=0.5\ kg$

Mass 2, $m_2=600\ g=0.6\ kg$

These two masses are attached to the 10 cm and 80 cm marks respectively of light meter scale. We need to find the moment of inertia of the system about an Axis passing through the center of the scales.

Distance from mass 1 to the center is, $r_1=0.4\ m$

and the distance from mass 2 to the center is, $r_2=0.3\ m$

The moment of inertia through the center of scales is given by :

$I=m_1r_1^2+m_2r_2^2\\\\I=0.5\cdot0.4^{2}+0.6\cdot0.3^{2}\\\\I=0.134\ kg-m^2$

So, the moment of inertia of the system about an axis passing through the center of the scales will be $0.134\ kg-m^2$. Hence, this is the required solution.

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