Question

Two masses of 50g and 100g are separated by a distance of 10m.what is the gravitational force of attraction between them

Answer 1

Question :-

Two masses of 50g and 100g are separated by a distance of 10m.what is the gravitational force of attraction between them.

Answer :-

→ Force = 0.3335 N

To find :-

Find the gravitational force of attraction.

Formula used :-

$\implies \: \boxed{\bf{ \: f \: = g \: \frac{ \: \: m_1\: m_2 \: }{ {r}^{2} } }} \\ \\ \bf{g \: is \: gravitational \: constant} \\ \\ \star \: \bf{value \: of \: g \: = 6.67 \times {10}^{ - 11} } \\ \\ \star \: \small\bf{ r \: is \: the \: distance \: between \: two \:} \\ \: \: \: \: \bf{masses}$

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Step - by - step explanation:-

Solution :-

Let the gravitational force of attraction is f ,

According to the question,

$m_1 = 50 \: g \: = 0.05 \: kg \\ \\ \: m_2 = 100 \: g \: = 0.1 \: kg \\ \\ \small \: \bf{ r \: (distance \: between \: masses) = 10 \: m}$

Now using the given formula ,

$\implies \: \small\bf{f \: = \frac{6.67 \times {10}^{ - 11} \times 0.1 \times 0.05 }{100} } \\ \\ \implies \: \bf{f \: = \frac{5 \times 667 \times {10}^{ - 11} }{10000000} } \\ \\ \implies \: \bf{ f \: = 3335 \times {10}^{ - 4} } \\ \\ \implies \: \boxed{ \bf{f \: = 0.3335 \: newton \: }}$

Therefore,the gravitational force of attraction is 0.3335 N.

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