Two masses of 5kg and 10 kg are connected to a pulley as shown. what will be the acceleration if the pulley is set free :(g=acceleration due to gravity )..
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We know that,
acceleration (a) = Force (F)/mass(m)
Let's assume that 10kg block is moving downwards direction.
On 5kg Block :-
T - mg = maT - 5(10) = 5aT - 50 = 5a........(1)
On 10kg Block :-
mg - T = ma10(10) - T = 10a100 - T = 10a.........(2)
From (1) and (2) :-
T - 50 = 5a..(1)100 - T = 10a..(2)
On adding both these equation we get,
50 = 15aa = 50/15a = 10/3m/s²
So, acceleration is 10/3 m/s²
acceleration (a) = Force (F)/mass(m)
Let's assume that 10kg block is moving downwards direction.
On 5kg Block :-
T - mg = maT - 5(10) = 5aT - 50 = 5a........(1)
On 10kg Block :-
mg - T = ma10(10) - T = 10a100 - T = 10a.........(2)
From (1) and (2) :-
T - 50 = 5a..(1)100 - T = 10a..(2)
On adding both these equation we get,
50 = 15aa = 50/15a = 10/3m/s²
So, acceleration is 10/3 m/s²
Answered by
1
Answer:
Explanation:
Equation of motion for
Equation of Motion for
- wherein
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