Question

Two masses of 8kg and 4kg are connected by a string as shown in figure over a frictionless pulley. The acceleration of the system in m/s2 will be

Answer 1

The acceleration will be zero.

Explanation:

m2g − T = m2a

T − Force applied on the pulley will be 100 N.

Tension in the string must be 50 N.

Now we will have

Force on 8 kg block:

8 g sin 30 - 4 g = 12 a  

0 = 12 a

a = 0 /12

a = 0

Weight of other block of mass 8 kg is 80 N.

As its weight is more than the tension in the string so this block will remain at rest and its acceleration must be zero.

Thus the acceleration will be zero.

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A block of mass 100 kg is set into motion on a friction less pulley and a rope system as shown in the figure . What horizontal force should be applied to produce in the block of an acceleration of 10 m/s^2.  ?

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