Question

Two masses of mass m1 and m2 are connected with a string of negligible mass, which passes over a friction less pulley, when the masses are released find the tension in string and acceleration of the mass.

Answer 1

Explanation:

Since, the masses are moving with constant velocity, there is no acceleration and hence no external force is acting on them.

Force balance:

For mass m

1

:

T

1

=m

1

g −−−−(i)

Formassm

3

T

2

=μm

3

g

T

2

=0.25×4×10

T

2

=10N

Formassm

2

:

T

1

=m

2

μgsinθ+m

2

gcosθ+T

2

T

1

=4×0.25×10×

5

3

+4×10×

5

4

+T

2

T

1

=6+32+10

T

1

=48N

Puttingin eqn(i)

48=m

1

×10

m

1

=4.8kg

Therefore,

The mass m

1

=4.8 kg and the tension in the horizontal spring T

2

=10N

I think this is u r answer