Physics, asked by zero6609, 1 year ago

Two masses m_{a}\ and\ m_{b} moving with velocities v_{a}\ and\ v_{b} in opposite direction collide elastically and after the collision m_{a}\ and\ m_{b} move with velocities v_{b}\ and\ v_{a} respectively. Then the ratio \frac{m_{a}}{m_{b}} is(a) \frac{V_{a}-V_{b}}{V_{a}+V_{b}}(b) \frac{m_{a}+m_{b}}{m_{a}}(c) 1 (d) \frac{1}{2}

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Answered by shobhit2502
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