Math, asked by beliciaobi2005, 12 hours ago

Two mathematically similar containers have heights of 30 cm and 75 cm.
The larger container has a capacity of 5.5 litres.
Calculate the capacity of the smaller container.
Give your answer in millilitres.

Answers

Answered by yadavmanoj728743
3

Step-by-step explanation:

V(small) = 352 milliliters the capacity of the smaller container is 352 milliliters Step-by-step explanation: Given that the two containers are similar, their dimensions follows the same ratio. Ratio of their length; Length(smaller) =30 cm Length(larger) = 75 cm Ratio = Length(smaller)/Length(larger) = 30cm/75cm Length Ratio = 2/5 The ratio of their Volumes will be; Ratio of volume = ratio of length raised to power three. Rv = Rl^3 Rv = (2/5)^3 Rv = 8/125 The volume of the smaller container; V(small) = Rv × V(large) Volume of larger container V(large) = 5.5 litres substituting the values; V(small) = 8/125 × 5.5 litres V(small) = 0.352 litres V(small) = 352 milliliters the capacity of the smaller container is 352 milliliters

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