Two men 960m apart stand at the same distance from a vertical hillock. One of them fires the shot and other hears the echo 2 sec after hearing the direct sound. find the distance of the men from the hillock assuming the velocity of sound as 320m/s.
Answers
Answer:
Step-by-step explanation:
Given: Distance between the two men = 800 m , v = 340 m/s , distance between the two men from the hillock is same.
Solution:
The time taken (t) for the direct sound to be heard by the other man = d / v
= 800/340 seconds
t = 40/17 seconds
Now, since the other man hears the echo 3s after the direct sound is heard ,
Therefore; total time taken(T) to hear the echo = ( t + 3 ) s
= 40/17 + 3
T = 92/17 seconds
Now;
T = 92/17 s , d (dist. of the two men from the hillock) = ? , v = 340m/s
Therefore;
distance of the two men from the hillock( = distance of one man from the hillock) = vT/2
= (340 × 92/17 × 1/2) m
= 920m (Ans)
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Given:
The distance between two men = 960 m
Speed of sound = 320 m/s
Time after which the other hears the echo when he has already heard the original sound = 2 sec
To find:
The distance between the two men.
Solution:
When the sound directly reaches the other man, the time taken will be:
Time = distance/ speed = 960/ 320 = 3 s
If the echo is heard after 2 sec, then time after which echo is heard is
t' = 3+2 sec = 5 sec
Therefore we can use the following relation now:
2d = t'* 320
d = 5 * 320/ 2 = 5* 160
= 800 m = 0.8 km
Therefore the distance of the men from the hillock is 0.8 km.