two men A and B are standing on opposite edge of a 6m long platform which is further kept on smooth floor.they start moving towards each other and finally meet at the midpoint of platform.find the displacement of platform if masses of A B and platform are 40kg,60kg,50 kg respectively
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Here is your answer
Given :-
two men A and B are standing on opposite edge of a 6m long.
Let M1 and M2 are two man.
Masses of A B and platform are 40kg,60kg,50 kg
We have to find displacement :-
Now
m1x1 = m2x2
Therfore,
60x + 50(6 -x ) = 40(6 +x)
60x + 300 – 50x = 240 + 40x
30x = 60
x = 2 meters.
Displacemnt of Platform => 6-x => 6-2 = 4 meters
Hope it helps you
Answered by
44
Answer: 0.4 m
Explanation: We assume that the displacement of platform is x.
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