Two men a and b, can do a piece of work in 9 hours and 18 hours respectively. If A,B and C working together can finish it in 5 hours,in how many hors will C alone do the same work?
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work done by a in 9 hours = 9
work done by a in 1 hour= 1/9 hours
work done by b in 18 hours= 18
work done by b in 1 hour = 1/18 hours
work done by a,b and c = 5 hours
work done by a, b and c in 1 hour= 1/5
so
now to find the value of c we must subtract the total work done by and b in 1 hour by a,b and c in 1 hour
(a+b+c) - ( a+b)
1/5-{1/9+1/18}
1/5-{2+1/18). LCM = 18
1/5-3/18
18-15/90. LCM= 90
3/90
1/30
.
. . work done by c in 1 hour is 1/30 so
work done by c = 30 hours
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