Two men a and b walk from p to q a distance of 21 km at rates 3 and 4 km an hour respectively. B reaches q and returns immediately and meets a at r. The distance from p to r is:
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Distance from P to Q ls 21 km.
Let A and B meet t hours after the start.
Distance travelled by A in t hours. = 31 km
Distance travelled by B in t hours
= 4tkm. Total distance travelled by both 4t + 3t = 71 km
When A and B meet, both would have travelled double the distance of PQ,
I.e., 21 x 2 = 42 km
71 = 42. 7t = 42 i / t = 6
.. they will meet at R. 18 km from P.
They will meet six hours from the start.
In 6 hours A will have travelled 6 * 3 = 18km
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