Question

Two men and secen boys can do piece of work in 4 days.It is done by 4 men and 4 boys in 3 days.how long would it take for one man or one boy to do it?

Answer 1

efficiency of m:b = 4:1

Answer 2

Answer:

15 days, 60 days

Step-by-step explanation:

(i)

2 men and 7 boys can do work in 4 days. That means in one day they can finish (1/4) work.

2m + 7b = (1/4).

(ii)

4 men and 4 boys can do work in 3 days. That means in 1 day they can finish (1/3) work.

4m + 4b = (1/3)

On solving (i) * 2 & (ii), we get

⇒ 4m + 14b = (1/2)

⇒ 4m + 4b = (1/3)

   -----------------------

            10b = 1/6

               b = 1/60.

Substitute b = (1/60) in (ii), we get

⇒ 4m + 4b = 1/3

⇒ 4m + 4(1/60) = 1/3

⇒ 4m + 1/15 = 1/3

⇒ 4m = 1/3 - 1/15

⇒ 4m = 4/15

⇒ m = 1/15

Therefore:

One men can finish the work in 15 days and 1 boy can finish it in 60 days.

Hope it helps!