Question

Two men and seven boys can do a piece of work in four days while four men and four bays can do it in three days how long would it take one man or one boy to do it alone?​

Answer 1

Let total work done be men be = X

Let total work done by boys be = y

then,

1 man's 1 day's work = 1/x

1 boy's 1 day's work = 1/y

according to data,

2/x + 7/y = 1/4 -----(1) (taking reciprocal of no of days)

and

4/x + 4/y = 3/y-----(2)

solving equations (1) and (2) through elimination,we get

X=15 and Y=60

thus one man takes 15 days to do work and one boy takes 60 days

Answer 2

Answer:

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