two men are on opposite sides of a tower. They observe the angles of elevation of the top of the tower as
60 and 45° respectively. If the height of the tower is 60m, then the distance between them is
a) 20(3- 3)
b) 20( 3-3)m
c) None of these
d) 20( 3+3)m
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Answer:
From 2nd man perspective,
tan45°=20/B
B=20m
From 1st man perspective,
tan60°=20/b
b=20/√3
b=20√3/3m
20-20√3/3=20(1-√3/3)
20(3-√3)m
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