two men are on the either side of a temple of 30 metres height observes its top at the angle of elevation of 30 degrees and 60 degrees respectively find the difference between them
aakankshakalra2:
apply tan 30 and tan 60 by taking two triangles and then add these two values
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tan 30=AD/DC⇒1/√3=30/DC
⇒DC=30 X √3=30x1.732=51.96m
tan 60=AD/BD⇒√3=30/BD
⇒BD=30/1.732=17.32m
TOTAL DISTANCE B/W THEM = 51.96+17.32=69.28m
⇒DC=30 X √3=30x1.732=51.96m
tan 60=AD/BD⇒√3=30/BD
⇒BD=30/1.732=17.32m
TOTAL DISTANCE B/W THEM = 51.96+17.32=69.28m
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