Question

two men are on the opposite sides of a tower they measure the angle of elevation of the top of the tower is 30 degree and 60 degree respectively if the height of the tower is 30 metres then the distance between the men is
​

Answer 1

Step-by-step explanation:

I hope it is correct, and it may help you

Answer 2

Answer:

40√3 metres

Step-by-step explanation:

In triangle ABD:

$tan 30^o = \frac{BD}{AD}$

$=> \frac{1}{\sqrt{3}} = \frac{30}{AD}$

$=> AD = 30\sqrt{3}$ metres          -- Equation 1

In triangle CBD:

$tan 60^o = \frac{BD}{DC}$

$=> \sqrt{3} = \frac{30}{DC}$

$=> DC = \frac{30}{\sqrt{3}}$ metres

$=> DC = \frac{30\sqrt{3}}{3} = 10\sqrt{3}$          -- Equation 2

On Adding Equation 1 and 2:

$AD + DC = 30\sqrt{3} + 10\sqrt{3}$

$=> AC = 40\sqrt{3}$

∴ AC = 40√3 metres [distance between the 2 men]

Refer to the attachment for better understanding. Please mark my answer brainliest if you got it and liked my way of explanation.