Two men can complete a piece of work in 6 days. Two women can complete the same piece of work in 9 days, whereas three children can complete the same piece of work in 8 days. Three women and four children worked together for 1 day. If only men were to finish the remaining work in 1 day how many total men would be required.
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if 2 men complete 'x' work in 6 days then
in 1 man will complete 'x/2' work in 6 days
and in one day 1 men will complete 'x/12'part of work
similarly 1 woman will complete 'x/18' part of work in one day and 1 child will complete 'x/24' part in one day
now acc to que
3women+4 children complete some amt of work rest is done by men
so women did 3x/18 =x/6 part of work
and children did 4x/24 = x/6 part of work
work left to be done= x-x/6-x/6
=2x/3
one man did x/12 part of work
then 2x/3 part will be done by=(12/x)(2x/3)
=8 men
in 1 man will complete 'x/2' work in 6 days
and in one day 1 men will complete 'x/12'part of work
similarly 1 woman will complete 'x/18' part of work in one day and 1 child will complete 'x/24' part in one day
now acc to que
3women+4 children complete some amt of work rest is done by men
so women did 3x/18 =x/6 part of work
and children did 4x/24 = x/6 part of work
work left to be done= x-x/6-x/6
=2x/3
one man did x/12 part of work
then 2x/3 part will be done by=(12/x)(2x/3)
=8 men
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