two men can do a piece of work in 3days and 6 days respectively .if they work together in how many days they finish the work
Answers
Answer :-
If both of them work together they can finish the work in 2 days.
Explanation :-
Given
One of the men can do a piece of work in 3 days
So, One of the men's 1 day work = 1/3
Another man can do a piece of work in 6 days
So, Another man's 1 day work = 1/6
We know that
Two men's 1 day work = One of the men's 1 day work + Another man's 1 day work
= (1/3) + (1/6)
Taking LCM
= (2 + 1)/6
= 3/6
= 1/2
Two men's 1 day work = 1/2
⇒ Two men can a piece of work in = 2 days
∴ If both of them work together they can finish the work in 2 days.
Rememer :
Total work done in = 'N' days
⇒ Work done in 1 days = (1/N) th amount of work
Also
Work done in one day = (1/N)th amount of work
⇒ Total work done in = 'N' days.
Let the men be A and B can complete the piece of work in x days
ATQ
A completes the work in 3 days
A does (1/3) part of work in 1 day
similarly
B completes the work in 6 days
B does (1/6) part of work in 1 day
So, if they work together, the portion of work they will complete in 1 day =
(1/3) + (1/6) = 1/2
So the time taken to complete the work by A and B together is (2/1) days = 2days
So 2 days is required answer.