two men can do a piece of work in 4days and 6 days respectively. if they work together, in how many days will they finish the work?
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Answer:
The first person can do a piece of work in 4 days.
⇒In one day he does, 1/4th part of work
⇒ The second person can do a piece of work in 6 days
⇒ In one day he does, 1/6th part of work.
If both of them work together,
Part of work done by them in single day
\begin{gathered} = \frac{1}{4} + \frac{1}{6} \\ \\ = \frac{3 + 2}{12} \\ \\ = \frac{5}{12} \end{gathered}
=
4
1
+
6
1
=
12
3+2
=
12
5
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