Two men can do a piece of work in 6 hours and 4 hours respectively. After the first has worked for 2 hours, he is joined by the other. By when should the work be completed ?
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Answers
Answer:
Step-by-step explanation:
st person can do 1 work in 6 hours
In 1 hour he does: 1/6 part of work
2nd person can do the same work in 4 hours
In 1 hour he does: 1/4 part of work.
1st person worked for 2 hours.
In 2 hours he did: 2*1/6 = 1/3 part of work
Work Remaining = 1 - 1/3 = 2/3 work
Now both the persons are working
In 1 hour both do: 1/6 + 1/4 = 2+3/12 = 5/12 work
1 hour== 5/12 work
X hours = 2/3 work
5X/12 = 2/3
X = 1.6 hours...
Hence the work will be completed in another 1.6 hours.
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Answer:
Step-by-step explanation:
As per question the individual have their own capacity of doing the work,per each hour as (1/6) & (1/4) respectively. Hence jointly they have the capability to the fraction of work in each hour =(1/6)+(1/4)=(5/12).As both together took over the left over work from the former after 2 hours=>The left over work=1-(2/6)=(1–1/3)=(2/3)rd part.So to complete the left over part jointly by the two={(2/3)/(5/12)=8/5hr=1.6hrs or 1hr 36 minutes next to joining of the two.Ans..
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