Two men can do a piece of work in 6 hours and 4 hours respectively. After the first has worked for 2 hours, he is joined by the other. By when should the work be completed ?
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Step-by-step explanation:
2 men can do a work in 6 hr and 4 hr respectively .
First man worked for 2 hours .
Then the other man joined .
First man complete it in 6 hr .
So in 1 hr he does 1/6 th of the work .
In 2 hr he does 1/3 rd .
So 1 - 1/3
= 2/3 rd part is left .
Both will now do the work .
Both can do : 1/4 + 1/6
= ( 3 + 2 )/12
= 5/12 th work in 1 hour
Let the time be x .
So 5/12 × x = 2/3
= 5 x / 12 = 2 / 3
= 5 x = 2 × 4
= x = 8/5 hrs
=
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