two men can do same piece of work in 6 hours and 4 hours respectively . after the first has worked for 2 hours , he is joined by others by when should the work be completer
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total work = 24
efficiency 1st - 4 , 2nd -6
a = 2× 4 = 8
remaining = 16 /10 = 1 ,6/10 will be the answer
efficiency 1st - 4 , 2nd -6
a = 2× 4 = 8
remaining = 16 /10 = 1 ,6/10 will be the answer
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