two men leave from the same place at the same time. One walks towards North at a speed of 3 km/hr and the other walks towards East at a speed of 4km/hr. Find thr distance between them at 1 hours
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1
Answer:
sory I can not answer
Step-by-step explanation:
Because I don't understand the question
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8
Answer:
(4T)²+(3T)²=(ST)² (using pythagoras theroem)
16T²+9T²= S²T²
25T²=S²T²
25T²/T² =S²
25=S²
S=✓25
S=5
D= (5×1) ( Distance=speed × Time)
D=5.
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