Question

Two men leave from the same place at the same time.One walks towards the north at a speed of 3km/hr and the other walk towards east at a speed of 4km/hr. Find the distance between them after 1 hour​

Answer 1

Answer:

(4T)²+(3T)²=(ST)² (using pythagoras theroem)

16T²+9T²= S²T²

25T²=S²T²

25T²/T² =S²

25=S²

S=✓25

S=5

D= (5×1) ( Distance=speed × Time)

D=5.