Question

two men on eitger side of a triangle 30 meter height observe it's top at the angle of elevation 30⁰ and 60⁰ respectively. find the distance between two mens​

Answer 1

Step-by-step explanation:

tan 30°=30/y1

y1=30/tan30°=30/1/√3=30√3

tan60°=30/y2

y2=30/tan60°=30/√3=10√3

y1+y2=30√3+10√3=40√3m