Question

Two men on either side of a temple 75m High have angles of elevation as 45° each. the distance between them is​

Answer 1

Answer:

Two persons are on either side of a temple, 75 m high, observe the angle of elevation of the top of the temple to be 30° and 60° respectively. The distance between the persons is

173.2 m

100 m

157.7 m

273.2 m

A.

173.2 m

Clearly, from the figure, the distance is BD = (BC + CD) m

In Δ ABC,

tan space 30 degree space space equals space AC over BC

fraction numerator 1 over denominator square root of 3 end fraction space equals space 75 over BC

BC space equals space 75 square root of 3 space straight m

In Δ ACD,

tan space 60 degree space equals space AC over BC

space space square root of 3 space equals space 75 over CD

CD space equals space fraction numerator 75 over denominator square root of 3 end fraction space cross times space fraction numerator square root of 3 over denominator square root of 3 end fraction space equals space fraction numerator 75 square root of 3 over denominator 3 end fraction

CD space equals space 25 square root of 3 space straight m

∴ Distance between both persons = BD = BC + CD

equals space 75 square root of 3 space plus space 25 square root of 3 space equals space 100 square root of 3

equals space 100 space cross times space 1.732 space equals space 173.2 space straight m

Answer 2

Step-by-step explanation:

Distances between two men is

175.3m