Question

Two men on either side of a temple 75m High have angles of elevation as 45° each. the distance between them is​

Answer 1

Answer:

BC=75m

Step-by-step explanation:

AB is a hight of two man. BC is the distance between the mans and the angle of elevation. Angle of elevation is <ACB=45°.

Distance between them=

tanC=AB/BC

or,ta45°=75/BC

or,. 1. =75/BC

or,1*BC=75

:.BC. =75m

answer.

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