Question

two men on either side of a temple of 30 meter Hight absorbed it's top at the elevation 30 and 60 degrees respectively. find the distance between the two men​

Answer 1

Answer:

Distance between the two men = 40√3 m

Step-by-step explanation:

Height of temple = 30 m

For man 1,

Angle of elevation = 60°

Let the distance between man 1 and temple be x m.

tan 60° = opposite/adjacent = 30/x

√3 = 30/x

x = 30/√3 = (10√3 × √3)/√3 = 10√3 m

For man 2,

Angle of elevation = 30°

Let the distance between man 2 and temple be y m.

tan 30° = opposite/adjacent = 30/y

1/√3 = 30/y

y = 30√3 m

Distance between the two men = x + y = 10√3 + 30√3 = 40√3 m