Two men on either side of the 70 m high building and in the line with base of building observe the angle of elevation of the top of the building as 30° and 60°. The distance between the two men using √3=1.73 is:-
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In △ABD,
tan30
o
=
AD
BD
3
1
=
AD
75
AD=75
3
m
In △BCD
tan60
o
=
CD
BD
3
=
CD
75
CD=
3
75
m
AC=AD+CD=(75+
3
75
)m
=
3
75(4)
=
1.73
300
=173.41 m
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