Question

Two men on either side of the cliff 75 m high observes the angles of elevation of the top of the cliff to be 30∘ and 60∘ respectively. Find the distance between the two men.

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Answer 1

Answer:

Step-by-step explanation:

let h be the height of the cliff and A and B be the point of observation and DC be the cliff

then in ∆ADC

tan 60°= p/b

√3 = 75/b1

b1 = 75/√3. ....(1)

and in ∆BDC

tan 30° = p/b

1/√3 = 75/b2

b2 = 75√3. ......(2)

on adding eq. (1) and(2) we get

b1+b2 = 75/√3+75√3

AB = (75+75)/√3

= 150/√3

= 50√3 Ans