two men on either sides of a Lighthouse observes the angle of elevation as 30° and 60° if the Lighthouse is 25 metres high then determine the distance between the two men
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The answer to this question is!!!!
Step-by-step explanation:
Given height of the Lighthouse AB = 75 m
Now in right-angled △ABC,
BC/AB = cot 30˚
= √3
⇒ BC/75 = √3
⇒ BC = 75√3 ….(i)
Also in right-angled △ABD,
BD/AB = cot 60˚
⇒ BD/75 = 1/√3
⇒ BD = 75/√3 × √3/√3
= 25√3 ……(ii)
Now the distance between the two men = CD
= BC + BD
= 75√3 + 25√3
= 100√3
Hence, the distance between two men
= 100√3 m
= 173.2 m
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