Two men start from points A and B respectively, 42 km apart.One walks from A to B at 4 km /hr and another walks from B to A a certain uniforn speed.They meet each other after 6 hours. Find the speed of second man
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t1-t2=6
d1/s1 -d2/s2=6
42/4 - 42/x =6
21/2 -6 =42/x
21-12/2 =42/x
9/2 =42/x
3/2 =14/x
3x=28
x=28/3
x=9.33kmph is answer
d1/s1 -d2/s2=6
42/4 - 42/x =6
21/2 -6 =42/x
21-12/2 =42/x
9/2 =42/x
3/2 =14/x
3x=28
x=28/3
x=9.33kmph is answer
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