Question

Two men, starting at the same point, walk in opposite directions for 4 meters, turn left and walk another 3 meters. what is the distance between them?

Answer 1

the difference b/w dem is 10 meters

Answer 2

Answer:

10 m.

Step-by-step explanation:

Refer the diagram

XZ =XQ

In Δ XYZ

$Hypotenuse^2= Perpendicular ^2 +Base^2$

$XZ^2= XY ^2 +YZ^2$

$XZ^2= 4^2 +3^2$

$XZ^2=16 +9$

$XZ^2=25$

$XZ=\sqrt{25}$

$XZ=5$

So, XZ =XQ =5

Distance between them = XZ+XQ=5+5=10 m

Hence the distance between them is 10 m.