Two metal A and B have work function 2eV and 6eV respectively .what is the ratio of their threshold frequency.
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Answer:
The formula for threshold wavelength λ is as follows:
λ = hc/ Φ
Where Φ is the work function of the metal,
h is Planck's constant,
c is the speed of light in vacuum.
Hc is a constant and threshold wavelength is inversely proportional to the work function of metal, therefore:
λA/ λB =ΦB/ ΦA
= 6/ 2 = 3
Therefore, the required ratio is 3:1.
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