two metal A and B have work functions 2 ev and 6ev respectively. what is the ratio of their threshold wavelength
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Given:
Work function of metal A = 2 eV
Work function of metal B = 6 eV
To find:
The ratio of their threshold wavelength.
Solution:
The formula for threshold wavelength λ is as follows:
λ = hc/ Φ
Where Φ is the work function of the metal,
h is Planck's constant,
c is the speed of light in vacuum.
hc is a constant and threshold wavelength is inversely proportional to the work function of metal, therefore:
λA/ λB = ΦB/ ΦA
= 6/ 2 = 3
Therefore the required ratio is 3:1.
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