Two metal plates are separated by 2 cm. The potentials of the plates are -10 V and +30 V. The electric field between the two plates is ........
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Given : Two metal plates are separated by 2 cm. The potentials of the plates are -10 V and +30 V.
To find : The electric field between the two plates.
solution : let A and B are two plates seperated by 2cm. The potential of plate A = -10 V and potential of plate B = + 30V
potential difference of Plates, ∆V =
= +30V - (-10V)
= 40V
seperation between plates, d = 2cm = 0.02m
so electric field, E = ∆V/d
= 40/0.02
= 2000 N/C
Therefore the electric field between plates is 2000 N/C.
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