two metal plates having charges q1 and q2 are placed close to each other to form a parallel plate capacitor of capacitance C then find the potential difference between the plates of the capacitor
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hello dear
here is your answer
potential difference between the plate of capacitor is c/q
hope it will help you
please mark it as brainliest
here is your answer
potential difference between the plate of capacitor is c/q
hope it will help you
please mark it as brainliest
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"a capacitor is a pair two conductors of any shape which are close to each other and have equal and opposite charges."-quoted from a physics text book.
so I assume that q1=q2
let it be equal to Q
then,the potential difference V=Q/C
Hope this helps you.
so I assume that q1=q2
let it be equal to Q
then,the potential difference V=Q/C
Hope this helps you.
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