Question

Two metal plates of same area and thickness
and I, are arranged in series. If the thermal
conductivities of the materials of the two plates
are k, and k. The thermal conductivity of the
combination is
2kk
1) ktk
kk (+1)
3) kl + keh
4) ktk​

Answer 1

Answer:

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Answer 2

Nice question mate !!!

Since the combination is made in series dQ/dt = const

From the reln,

dQ/dt = K A (ΔФ) / dx

ΔФ ∝ 1/k

from this 1/Keq = 1/K₁ + 1/K₂

Keq = K/2

Hope this helps !!!

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