Two metal rods A and B have good Shining, while it exposed to air for some time. The metal A loses its shining faster as compared to metal B
(a) Why metal A loses its shining appearance at faster rate when compared to Metal B? Justify it based on the reactivity series.
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Answer:
Hello friend! Here is your answer....
Explanation:
The metals lose their shine on brightness on keeping in air for a long time due to formation of a thin layer of oxide, carbonate or sulphide on their surface by the slow action of various gases present in air.
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It's probably because Metal A is more reactive than Metal B. So metal A reacted with the moisture in the air to form a layer of its oxide faster than B and lost its luster.
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