Two metal spheres of capacitance C1 and C2 carry some charges. They are put in contact and then separated. The final charges Q1 and Q2 on them will satisfy
(a) Q1Q2
(b) Q1Q2=C1C2
(c) Q1Q2>C1C2
(d) Q1Q2=C2C1.
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Answer:
c) Q1Q2>C1C2
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(b) The final charges are equal with the capacitance, i.e., Q1Q2=C1C2
Explanation:
- When two metal spheres containing the capacitance C1 and C2 are connected, until both the spheres attain the same common potential V, the charges will flow between them.
- Please note, Q1 = C1•V ; So V = Q1/C1 …(1)
- And Q2 = C2•V ; So V = Q2/C2 …(2)
- From the above equation (1) and (2), we can write
- Q1/C1 = Q2/C2
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